Asked by fizz
helo sir/madam
can u help me to solve this problem
sOLVE 2log 15 +log(5-x)- log4x=2
can u help me to solve this problem
sOLVE 2log 15 +log(5-x)- log4x=2
Answers
Answered by
Reiny
3 important rules of logs
1. log (AB) = log A + log B
2. log(A/B) = log A - log B
3. log A^n = nlogA
so 2log15 + log(5-x) - log 4x = 2
log 15^2 + log(5-x) - log 4x = 2
log (225(5-x)/(4x) ) = 2
225(5-x)/(4x) = 10^2 = 100
400x = 1125 - 225x
625x = 1125
x = 1125/625 = 9/5 or 1.8
1. log (AB) = log A + log B
2. log(A/B) = log A - log B
3. log A^n = nlogA
so 2log15 + log(5-x) - log 4x = 2
log 15^2 + log(5-x) - log 4x = 2
log (225(5-x)/(4x) ) = 2
225(5-x)/(4x) = 10^2 = 100
400x = 1125 - 225x
625x = 1125
x = 1125/625 = 9/5 or 1.8
Answered by
Awuku
ROCKSON BEDI
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