Asked by RhUaNg

Let M be the midpoint of side \overline{AB} of \triangle ABC. Angle bisector \overline{AD} of \angle CAB and the perpendicular bisector of side \overline{AB} meet at X. If AB = 40 and MX = 9, then how far is X from line {AC}?
Answered by Anonymous
i don't know son
Answered by Anonymous
54
Answered by ANYONUMES
54 is NOT correct
Answered by Anonymous
The answer is 9 for everyone who needs it. And it is correct, I checked.
Answered by Anonymous
is 9 right anonymous
Answered by Anonymous
its 9
Answered by sdf
dfs
Answered by tyu
tyuuuuuuuuuuuu








Answered by Someone
Yea, i dunno. i gotta do this but with 44 and 12
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