ANYONUMES

15 is not correct

54 is NOT correct

Triangles $PAB$ and $PCD$ are similar, so \[\frac{[PAB]}{[PCD]} = \left( \frac{AB}{CD} \right)^2 = \frac{x^2}{y^2}.\] But we are given that $[PAB] = 8$ and $[PCD] = 18$, so \[\frac{x^2}{y^2} = \frac{8}{18} = \frac{4}{9},\] which means $x/y = 2/3$. Then $A...