Asked by SHIV
At 450oC the value of equilibrium constant for the following system is 6.59 x 10-3. If [NH3] = 1.23 x 10-4 and [H2] = 2.75 x 10-3 at equilibrium, determine the concentration of N2 at that point.
N2(g) + 3H2(g) 2NH3(g)
N2(g) + 3H2(g) 2NH3(g)
Answers
Answered by
DrBob222
Do you mean at equilibrium (NH3) = 1.23E-4M?
and (H2) at equilibrium = 2.75E-3M?
that is, is that M?
........N2 + 3H2 ==> 2NH3
E.......x....2.75E-3....1.23E-4M
Keq = (NH3)^2/(x)(H2)^3
Substitute and solve for x
and (H2) at equilibrium = 2.75E-3M?
that is, is that M?
........N2 + 3H2 ==> 2NH3
E.......x....2.75E-3....1.23E-4M
Keq = (NH3)^2/(x)(H2)^3
Substitute and solve for x