Asked by Anonymous
At 500 ºC, the decomposition of water into hydrogen and oxygen,
2H2O(g) 2H2(g) + O2(g)
has Kc = 6.0 × 10-28. What are the concentrations of H2 and O2 that are present at equilibrium in a 2.00 L reaction vessel at this temperature if the container originally held 0.086 mol H2O?
2H2O(g) 2H2(g) + O2(g)
has Kc = 6.0 × 10-28. What are the concentrations of H2 and O2 that are present at equilibrium in a 2.00 L reaction vessel at this temperature if the container originally held 0.086 mol H2O?
Answers
Answered by
DrBob222
(H2O( = 0.0860 mol/2.00L = approx 0.043M
............2H2O --> 2H2 + O2
I..........0.043......0.....0
C...........-2x...... 2x....x
E..........0.043-2x...2x....x
Substitute the E line into the Kc expression and solve for x.
............2H2O --> 2H2 + O2
I..........0.043......0.....0
C...........-2x...... 2x....x
E..........0.043-2x...2x....x
Substitute the E line into the Kc expression and solve for x.
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