Okay now. New question. Find the number of (m) ways in which 6 people can ride a toboggan if ONE OUT OF THREE people must drive.

If you mean that the 6-person team must contain 3 drivers, then

the driver can be selected in 3 different ways

The remaining 5 riders can be arranged in P(5) = 5! ways

If I have misread the problem, please clarify.

I think you kind of misread it.

I meant that there was ONE driver, although you pick 1 driver out of THREE drivers. Thank you for your time though.

Can anyone answer my question?

If you read carefully, I think you will find I did. 3 ways to choose the driver,

5! ways to arrange the riders.

thank you for your help!

there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three wasmys to select 1 driver. we minus 1 from the six people then we be left by 5...5!.

the answer is: 3×5!= 360 ways

there are six people and on the selected 3, 1 must be a driver. so out of the three selected, there are three ways to select 1 driver. we minus 1 from the six people then we be left by 5...5!.

the answer is: 3×5!= 360 ways