Question

An amusement park ride can hold up to 19 riders. At closing time, there are still 67 people in line for the ride. The ride operator will put as many people onto the ride as he can.

How many more times will the ride have to operate so that everyone in line can get a ride?


Responses

4
4

3
3

10
10

9

Answer 1

To determine how many more times the ride has to operate to accommodate all 67 people in line, we can divide the total number of people by the maximum number of riders the ride can hold at once.

The ride can hold 19 riders at a time.

So, we calculate:

\[
\text{Number of rides needed} = \frac{67}{19}
\]

Calculating this gives:

\[
67 \div 19 \approx 3.5263
\]

Since the number of rides must be a whole number, we round this up to the next whole number, which is 4. This means the ride will need to operate 4 times in total.

To confirm, we can calculate how many people will be accommodated in 3 rides:

\[
3 \times 19 = 57 \text{ people}
\]

This leaves:

\[
67 - 57 = 10 \text{ people}
\]

So 3 rides accommodate 57 people, and there are still 10 people left. Therefore, the 4th ride will have to take the remaining 10 people.

Thus, the ride will have to run **4 more times** to ensure everyone in line gets a ride.

The answer is **4**.