Asked by Ollie
sodium chloride (relative molecular mass = 58.5) had a solubility of 36.0 g per 100g of water. the density of the solution is 1.13 g/ml. which of the following calculations would give te solubility in moles per liter?
A) 36.0 x 10/58.5
b) 36.0 x 10 x 1.13/(58.5 x 136)
c) 36.0 x 1000/(58.5 x 1.13)
d) 36.0 x 1000 x 1.13/(58.5 x 136)
A) 36.0 x 10/58.5
b) 36.0 x 10 x 1.13/(58.5 x 136)
c) 36.0 x 1000/(58.5 x 1.13)
d) 36.0 x 1000 x 1.13/(58.5 x 136)
Answers
Answered by
DrBob222
M = mols/L
mol = 36.0/58.5
volume = mass/density = 136/(1.13*1000)
So M = (36.0/58.5)/[136/(1.13*1000]
Check me out on this. This would make it
(36.0/58.5) x (1.13*1000/136) =
(36.0 x 1.13 x 1000/136 x 58.5 = ?
mol = 36.0/58.5
volume = mass/density = 136/(1.13*1000)
So M = (36.0/58.5)/[136/(1.13*1000]
Check me out on this. This would make it
(36.0/58.5) x (1.13*1000/136) =
(36.0 x 1.13 x 1000/136 x 58.5 = ?
Answered by
Ollie
thanks! where is the 136 coming from tho??
Answered by
Maria
It's the total mass of the solution: 36g of NaCl and 100g of water.
Answered by
Waseem khan
Why we write 1000 with density
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.