Question
sodium chloride (relative molecular mass = 58.5) had a solubility of 36.0 g per 100g of water. the density of the solution is 1.13 g/ml. which of the following calculations would give te solubility in moles per liter?
A) 36.0 x 10/58.5
b) 36.0 x 10 x 1.13/(58.5 x 136)
c) 36.0 x 1000/(58.5 x 1.13)
d) 36.0 x 1000 x 1.13/(58.5 x 136)
A) 36.0 x 10/58.5
b) 36.0 x 10 x 1.13/(58.5 x 136)
c) 36.0 x 1000/(58.5 x 1.13)
d) 36.0 x 1000 x 1.13/(58.5 x 136)
Answers
M = mols/L
mol = 36.0/58.5
volume = mass/density = 136/(1.13*1000)
So M = (36.0/58.5)/[136/(1.13*1000]
Check me out on this. This would make it
(36.0/58.5) x (1.13*1000/136) =
(36.0 x 1.13 x 1000/136 x 58.5 = ?
mol = 36.0/58.5
volume = mass/density = 136/(1.13*1000)
So M = (36.0/58.5)/[136/(1.13*1000]
Check me out on this. This would make it
(36.0/58.5) x (1.13*1000/136) =
(36.0 x 1.13 x 1000/136 x 58.5 = ?
thanks! where is the 136 coming from tho??
It's the total mass of the solution: 36g of NaCl and 100g of water.
Why we write 1000 with density
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