Asked by anonymous
what is the number of moles of nonvolatile nonelectrolyte dissolved in 3.5 kg of water when the solution boils at 101.86 degrees C
Answers
Answered by
DrBob222
delta T = Kb*m
delta T = 101.86 - normal boiling point.
Substitute and solve for m = molality.
m = mols/Kg solvent. You know kg solvent and m, solve for mols.
delta T = 101.86 - normal boiling point.
Substitute and solve for m = molality.
m = mols/Kg solvent. You know kg solvent and m, solve for mols.
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