Asked by TT
Simplify
(2/3k)+(k/k+1) divided by (k/k+1) -(3/k)
(2/3k)+(k/k+1) divided by (k/k+1) -(3/k)
Answers
Answered by
Steve
(2/3k)+(k/k+1) = (3k^2+2k+2)/(3k(k+1))
(k/k+1) -(3/k) = (k^2-3k-3)/(k(k+1))
divide the two and you have
(3k^2+2k+2) / 3(k^2-3k-3)
(k/k+1) -(3/k) = (k^2-3k-3)/(k(k+1))
divide the two and you have
(3k^2+2k+2) / 3(k^2-3k-3)
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