A catapult launches a boulder with an upward velocity of 184 feet per second. The height of the boulder, (h), in feet after t seconds is given by the function h(t) = –16t² + 184t +20. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.

5 answers

for any quadratic of the form
y = ax^2 + bx + c

the x of the vertex is -b/(2a)
so for yours ...
x of the vertex is -184/(-32) = 5.75

so it took 5.75 seconds,

plug that into your original function to find the maximum height.
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