Asked by Sandra

A catapult launches a boulder with an upward velocity of 184 feet per second. The height of the boulder, (h), in feet after t seconds is given by the function h(t) = –16t² + 184t +20. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary.
Answered by Reiny
for any quadratic of the form
y = ax^2 + bx + c

the x of the vertex is -b/(2a)
so for yours ...
x of the vertex is -184/(-32) = 5.75

so it took 5.75 seconds,

plug that into your original function to find the maximum height.
Answered by Hello
wow you guys are from the 2014. man those where good times
Answered by Hello
where is my call of duty people at?
Answered by Anonymous
I'M HERE WITH YOU, HELLO. MY GUY 2014 WAS A GOOD YEAR FOR COD

Answer
How time flies I swear
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