Asked by Amy
                Last week i did a lab and i just wanted to show you my results because my computer was acting weird when i used the voltage probe.(I just needed you to check that the cathode and anodes  and voltages make sense)
CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
CuSO4(cathode)and ZnSO4(anode)--[-0.484]
            
            
        CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
CuSO4(cathode)and ZnSO4(anode)--[-0.484]
Answers
                    Answered by
            DrBob222
            
    <b> I can't check any of the voltages; I assume these were at other than 1 M. For the Al/Cu (#1 below) the voltage would be about 2.0 volts for 1 M solutions of each. Also, it MIGHT be possible, for some that I have suggested as the other way around below, could be correct if the concentrations were not 1 M.
</b>
CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
<b>OK.</b>
cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
<b>I think Zn is the anode and Cu is the cathode.</b>
MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
<b>OK</b>\
ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
<b>I think Al is the anode and Zn is the cathode.</b>
Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
<b>OK</b>
CuSO4(cathode)and ZnSO4(anode)--[-0.484]
<b>OK</b>
    
</b>
CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
<b>OK.</b>
cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
<b>I think Zn is the anode and Cu is the cathode.</b>
MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
<b>OK</b>\
ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
<b>I think Al is the anode and Zn is the cathode.</b>
Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
<b>OK</b>
CuSO4(cathode)and ZnSO4(anode)--[-0.484]
<b>OK</b>
                    Answered by
            amy
            
    They are 0.1 M solutions. I have tons of post lab dicussion questions you think you can help me with them? I don't even know where to start
    
                    Answered by
            DrBob222
            
    I suppose what you posted above are some of the tons of discussion questions. I think I answered one of them completely enough that you can follow that for the others. 
    
                    Answered by
            SHENBAGARAJ. M
            
    Dear sir
Good morning Sir we run a Company SENDHOOR CHEMICAS and we supply mag
    
Good morning Sir we run a Company SENDHOOR CHEMICAS and we supply mag
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.