Question

Last week i did a lab and i just wanted to show you my results because my computer was acting weird when i used the voltage probe.(I just needed you to check that the cathode and anodes and voltages make sense)

CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]

cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]

MgSO4(anode)and ZnSO4(cathode)--[0.284 V]

ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]

Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]

CuSO4(cathode)and ZnSO4(anode)--[-0.484]

Answer 1

<b> I can't check any of the voltages; I assume these were at other than 1 M. For the Al/Cu (#1 below) the voltage would be about 2.0 volts for 1 M solutions of each. Also, it MIGHT be possible, for some that I have suggested as the other way around below, could be correct if the concentrations were not 1 M.
</b>
CuSO4(cathode)and Al2(SO4)3 (anode)--[0.050V]
<b>OK.</b>

cuSO4(anode) and ZnSO4(cathode)-- [0.048 V]
<b>I think Zn is the anode and Cu is the cathode.</b>

MgSO4(anode)and ZnSO4(cathode)--[0.284 V]
<b>OK</b>\

ZnSO4(anode) and AlSO4(cathode)-- [-0.056V]
<b>I think Al is the anode and Zn is the cathode.</b>

Al2(SO4)3(cathode) and MgSO4(anode)--[0.966 V]
<b>OK</b>

CuSO4(cathode)and ZnSO4(anode)--[-0.484]
<b>OK</b>

Answer 2

They are 0.1 M solutions. I have tons of post lab dicussion questions you think you can help me with them? I don't even know where to start

Answer 3

I suppose what you posted above are some of the tons of discussion questions. I think I answered one of them completely enough that you can follow that for the others.

Answer 4

Dear sir
Good morning Sir we run a Company SENDHOOR CHEMICAS and we supply mag