Question
only 65% of climbers reach the summit, a random sample of 16 climbers what is the probability that(A) all 16 reach (B) at least 10 reach (C) no more than 12 reach
Answers
Kuai
a. P(all) = 16C16(.65)^16 (.35)^0 = 0.0010153
b. P(at least 10) = P(=>10) = 1-P(k<=9)
1-Binomcdf(16,.65,9)= 0.6881
c. P(no more than 12) = P(k <= 12)
Binomcdf(16, .65, 12) = 0.8661
b. P(at least 10) = P(=>10) = 1-P(k<=9)
1-Binomcdf(16,.65,9)= 0.6881
c. P(no more than 12) = P(k <= 12)
Binomcdf(16, .65, 12) = 0.8661