In falling freely 1.7 m, both climbers reach a velocity of sqrt(2g*1.7) = 5.77 m/s and a kinetic energy M g *1.7
The average force needed to stop in a distance is given by
F = KE/X = 1.7Mg/X
That is 1.7/1 = 1.7 times the body weight for Karen and 1.7/0.25 = 6.8 times the body weight of Bill
How would you answer the last question?
Two rock climbers, Bill and Karen, use safety ropes of similar length. Karen's rope is more elastic, called a dynamic rope by climbers. Bill has a static rope, not recommended for safety purposes in pro climbing. Karen falls freely about 1.7 m and then the rope stops her over a distance of 1.0 m.
(a) Estimate, assuming that the force is constant, how large a force she will feel from the rope. (Express the result in multiples of her weight.)
____ xKaren's weight
(b) In a similar fall, Bill's rope stretches by 25 cm only. How many times his weight will the rope pull on him?
___ x Bill's weight
Which climber is more likely to be hurt?
a) Bill
b) Both are equally subject to injury.
c) Karen
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