Asked by anonymous
What is the focus and directrix of the graph: x-3y^2=0?
Answers
Answered by
Henry
X = 3y^2
K = Yv = -B/2A = 0/6 = 0
h = Xv = 3 * 0^2 = 0
D(X1,K), V(h,K), F(X2,K).
D(X1,0), V(0,0), F(X2,0)
DV = 0-X1 = 1/4a = 1/12
0-X1 = 1/12
X1 = -1/12
VF = X2-0 = 1/4a = 1/12
X2 = 1/12
K = Yv = -B/2A = 0/6 = 0
h = Xv = 3 * 0^2 = 0
D(X1,K), V(h,K), F(X2,K).
D(X1,0), V(0,0), F(X2,0)
DV = 0-X1 = 1/4a = 1/12
0-X1 = 1/12
X1 = -1/12
VF = X2-0 = 1/4a = 1/12
X2 = 1/12