Asked by Runtafus
Solve:
6c3
A.120
B.720
C.20
D.240
How many ways can you choose 3 dishes from a menu of 8?
A.24
B.336
C.144
D.56
Solve 6p4
A.240
B.720
C.20
D.360
6c3
A.120
B.720
C.20
D.240
How many ways can you choose 3 dishes from a menu of 8?
A.24
B.336
C.144
D.56
Solve 6p4
A.240
B.720
C.20
D.360
Answers
Answered by
Reiny
you should know these w definitions
nCr = n!/( r!(n-r)! )
nPr = n!/(n-r)!
6C3 = 6!/(3!3!) = 20
6P4 = 6!/2! = 360
On most scientific calculators both of these functions are built-in
on mine they are found below the 5 - key and the 6-key
to do 6C3
enter
6
2ndF
5
3
=
to get 20
How many ways can you choose 3 dishes from a menu of 8?
8C3 = 56
nCr = n!/( r!(n-r)! )
nPr = n!/(n-r)!
6C3 = 6!/(3!3!) = 20
6P4 = 6!/2! = 360
On most scientific calculators both of these functions are built-in
on mine they are found below the 5 - key and the 6-key
to do 6C3
enter
6
2ndF
5
3
=
to get 20
How many ways can you choose 3 dishes from a menu of 8?
8C3 = 56
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