Question

the longer legs of a right triangle is 20 cm more than twice the length of the shorter leg. The length of the hypotenuse is 22 cm more than twice the length of the shorter leg. Find the side lengths of the triangle

Answer 1

x^2 + (2x+20)^2 = (2x+22)^2

x^2+ 4 x^2 + 80 x + 400 = 4 x^2+88x + 484

x^2 - 8 x - 84 = 0
(x-14)(x+6) = 0
x = 14
2x+20 = 48
2x+22 = 50