Asked by verenice
the legs of a right angled triangle are 5 cm and 12cm long. find the lengths, to the tenth, of the segment into which the bisector of the right angle divides the hypotenuse.
Answers
Answered by
Reiny
Let ABC be the right-angled triangle with angleB = 90°
let the bisector angle B be BD where D is on the hypotenuse AC
We know that AD : DC = areaABD : areaBCD
areaABD = (1/2)(12)(BD)sin45°
areaBCD = (1/2)(5)(BD)sin45°
then areaABD : areaBCD = 12 : 5
so AD = (12/17)(13) = 9.2
and DC = 13-9.2 = 3.8
let the bisector angle B be BD where D is on the hypotenuse AC
We know that AD : DC = areaABD : areaBCD
areaABD = (1/2)(12)(BD)sin45°
areaBCD = (1/2)(5)(BD)sin45°
then areaABD : areaBCD = 12 : 5
so AD = (12/17)(13) = 9.2
and DC = 13-9.2 = 3.8
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