first
http://www.wolframalpha.com/input/?i=plot++e^%28-5x^2%29
At what interval is e^(-5x^2) concave up?
I know the second derivative is
100x^2*e^-5x^2-10*e^-5x^2
but I just can not figure this one out.
Thank you for your help!
4 answers
first
http://www.wolframalpha.com/input/?i=plot++e^%28-5x^2%29
Then this for second derivative and graph
https://www.wolframalpha.com/input/?i=second+derivative+of+e^%28-5x^2%29
http://www.wolframalpha.com/input/?i=plot++e^%28-5x^2%29
Then this for second derivative and graph
https://www.wolframalpha.com/input/?i=second+derivative+of+e^%28-5x^2%29
Note that you did the second derivative correctly. It is easier to write it their way y" = 10e^(-5x^2)(10x^2-1)
It is zero at x = +/- .316
It is zero at x = +/- .316
so it is positive for x>.316
and for x <.316
and for x <.316