Asked by Lue
The perimeters of 2 similar polygons are 12 and 16.
1. What is the ratio of the lengths of 2 corresponding sides?
2. What is the ratio of the areas?
3. If the area of the smaller polygon is 54 what is the area of the larger polygon?
1. What is the ratio of the lengths of 2 corresponding sides?
2. What is the ratio of the areas?
3. If the area of the smaller polygon is 54 what is the area of the larger polygon?
Answers
Answered by
Damon
ratio of ANY lengths in similar figures is the same 12/16 = 3/4
2. Ratios of ANY areas is length ratio squared 9/16
3. 54 * 16/9 = 96
2. Ratios of ANY areas is length ratio squared 9/16
3. 54 * 16/9 = 96