Asked by Keyonna

The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 square units, what is the area of the larger square?

Answers

Answered by Reiny
Since both the length of sides and perimeter are linear

the perimeters would be in that same ratio as the sides.
So the sides are in the ratio of 5:4

The ratio of areas is equal to the square of their corresponding sides.
so
A/32 = 5^2 / 4^2
A = 32(25)/16 = 50
Answered by Abdul-Rehman
If Smaller square = 32
Perimeter of Small Square = 4x
Perimeter of Larger Square = 5x
Perimeter Of Small Square = 4L
4x = 32
x = 32 / 4
x = 8
Then
5x = 5(8)
5x = 40

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