Asked by Keyonna
The ratio of the perimeters of two similar squares is 5 to 4. If the area of the smaller square is 32 square units, what is the area of the larger square?
Answers
Answered by
Reiny
Since both the length of sides and perimeter are linear
the perimeters would be in that same ratio as the sides.
So the sides are in the ratio of 5:4
The ratio of areas is equal to the square of their corresponding sides.
so
A/32 = 5^2 / 4^2
A = 32(25)/16 = 50
the perimeters would be in that same ratio as the sides.
So the sides are in the ratio of 5:4
The ratio of areas is equal to the square of their corresponding sides.
so
A/32 = 5^2 / 4^2
A = 32(25)/16 = 50
Answered by
Abdul-Rehman
If Smaller square = 32
Perimeter of Small Square = 4x
Perimeter of Larger Square = 5x
Perimeter Of Small Square = 4L
4x = 32
x = 32 / 4
x = 8
Then
5x = 5(8)
5x = 40
Perimeter of Small Square = 4x
Perimeter of Larger Square = 5x
Perimeter Of Small Square = 4L
4x = 32
x = 32 / 4
x = 8
Then
5x = 5(8)
5x = 40
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