Asked by Amy
If Mike has 8 dimes and 6 pennies in his pocket. If he randomly selected one coin and then a second coin without replacing the first, what is the probability that both coins were dimes?
Answers
Answered by
Reiny
prob(2dimes) = (8/14)(7/13)
= 4/13
= 4/13
Answered by
BOLAJI Oretan
Probability of choosing the first coin (dime) = 8/14
Probability of choosing the second without replacement = 7/13
Probability of choosing the first AND second = (8/14)(7/13)=4/13
Probability of choosing the second without replacement = 7/13
Probability of choosing the first AND second = (8/14)(7/13)=4/13
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