Asked by rosaline
DAmon you equaled them to zero that is not rightt
An open-topped box can be made from a rectangular sheet of aluminum,
an open-topped box can be made from a rectangular sheet of aluminum, with dimensions 40 cm by 25 cm, by cutting equal-sized squares from the four corners and folding up the sides.
Declare your variables and write a function to calculate the volume of a box that can be formed.
I figured out this part because the function would be f(x)=x(25-2x)(40-2x)
x being the height
25-2x being the width
40-2x being length
Then it asks what cut lengths to the nearest hundredth are acceptable if the volume of the box must be between 1512 and 2176cm^3.
So you would the write 1512<x(40-2x)(25-2x)<2176
how to you solve the inequality to get the x
PLEASE HELP THNX I HAVE A TEST TMR
An open-topped box can be made from a rectangular sheet of aluminum,
an open-topped box can be made from a rectangular sheet of aluminum, with dimensions 40 cm by 25 cm, by cutting equal-sized squares from the four corners and folding up the sides.
Declare your variables and write a function to calculate the volume of a box that can be formed.
I figured out this part because the function would be f(x)=x(25-2x)(40-2x)
x being the height
25-2x being the width
40-2x being length
Then it asks what cut lengths to the nearest hundredth are acceptable if the volume of the box must be between 1512 and 2176cm^3.
So you would the write 1512<x(40-2x)(25-2x)<2176
how to you solve the inequality to get the x
PLEASE HELP THNX I HAVE A TEST TMR
Answers
Answered by
Damon
I set them equal to 1512
and then to 2176
THEN
I subtracted 1512 from the first both sides
AND
I subtracted 2176 from the second both sides
PLEASE calm down and think
and then to 2176
THEN
I subtracted 1512 from the first both sides
AND
I subtracted 2176 from the second both sides
PLEASE calm down and think
Answered by
rosaline
ya but they are inequalities
1512<x(40-2x)(25-2x)<2176
it does not equal 1512 it is bigger than it hence this (<)
1512<x(40-2x)(25-2x)<2176
it does not equal 1512 it is bigger than it hence this (<)
Answered by
rosaline
so wouldnt it be
4x^3 - 130x^2 + 1000x - 1512 > 0 instead of equalling
4x^3 - 130x^2 + 1000x - 1512 > 0 instead of equalling
Answered by
Damon
I did the two equations at the limits and said look between them
Answered by
Damon
go back to where Steve is helping you as well and look at the graphs. Watch out though, the third region makes the box higher than half the width so will not work.
Answered by
Damon
If you are still stuck, look at the graphs Steve linked you to carefully and see three areas between the curves on the x axis. Those are values of x where your original function is between the limits. The last area on the right is not feasible because the width would be negative if the box were that high.
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