Asked by Anonymous
What is the exact value of sin(2 theta) if cos theta= 3/5 and theta is in quadrant IV?
Answers
Answered by
Steve
in QIV,
cosθ = 3/5
sinθ = -4/5
and you know that
sin2θ = 2sinθ cosθ
So, plug and chug
cosθ = 3/5
sinθ = -4/5
and you know that
sin2θ = 2sinθ cosθ
So, plug and chug
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