Asked by Wally
How would you get the exact value of the following problem:
29 * 6^(-3x) = 11
Thanks!
29 * 6^(-3x) = 11
Thanks!
Answers
Answered by
Steve
divide by 29:
6^(-3x) = 11/29
take log of both sides
-3x = log(11/29)
x = -log(11/29)/3
or, x = log(29/11)/3
6^(-3x) = 11/29
take log of both sides
-3x = log(11/29)
x = -log(11/29)/3
or, x = log(29/11)/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.