Asked by Anonymous
                How to solve y = -0.04x^2 + 1.3x + 56 using the quadratic formula?
            
            
        Answers
                    Answered by
            bobpursley
            
    Solve?  You mean the zeroes?
y=0=-0.04x^2 + 1.3x + 56
x=(1.3 +-sqrt(1.3^2+3*.04*56)/(.08)
do the math.
    
y=0=-0.04x^2 + 1.3x + 56
x=(1.3 +-sqrt(1.3^2+3*.04*56)/(.08)
do the math.
                    Answered by
            Anonymous
            
    Do you mean 4*0.4? And how did you get positive 0.4? That was the part that confused me.
    
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