Asked by Anonymous
Solve the system of equations
y=-2(x^2-1)
y=2(x^4-2x^2 +1)
y=-2(x^2-1)
y=2(x^4-2x^2 +1)
Answers
Answered by
Steve
The second equation is
y = 2(x^2-1)^2
so,
-2(x^2-1) = 2(x^2-1)^2
so, x^2-1=0 is a solution, meaning x = ±1
Otherwise, divide by 2(x^2-1) to get
-1 = (x^2-1)
x = 0
So, the solutions are -1,0,1
View the graphs at
http://www.wolframalpha.com/input/?i=solve+y%3D-2%28x^2-1%29%2C+y%3D2%28x^4-2x^2+%2B1%29
y = 2(x^2-1)^2
so,
-2(x^2-1) = 2(x^2-1)^2
so, x^2-1=0 is a solution, meaning x = ±1
Otherwise, divide by 2(x^2-1) to get
-1 = (x^2-1)
x = 0
So, the solutions are -1,0,1
View the graphs at
http://www.wolframalpha.com/input/?i=solve+y%3D-2%28x^2-1%29%2C+y%3D2%28x^4-2x^2+%2B1%29
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