Starting with an initial speed of 5.00 m/s at a height of 0.335 m, a 1.75-kg ball swings downward and strikes a 4.40-kg ball that is at rest, as the drawing shows.

Question

(a) Using the principle of conservation of mechanical energy, find the speed of the 1.75-kg ball just before impact.
m/s

(b) Assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision.
m/s (1.75 kg-ball)
m/s (4.40 kg-ball)

(c) How high does each ball swing after the collision, ignoring air resistance?
m (1.75 kg-ball)
m (4.40 kg-ball)

Answer 1

(a) 4.45 m/s
(b) 2.22 m/s (1.75 kg-ball), 2.78 m/s (4.40 kg-ball)
(c) 0.67 m (1.75 kg-ball), 0.89 m (4.40 kg-ball)