Asked by joseph
starting with an initial speed of 5.00 m/s at a height of 0.265 m, a 1.75 kg ball swings downward and strikes a 4.45 kg ball that is at rest, as the drawing shows.
(a) Using the principle of conservation of mechanical energy, find the speed of the 1.75 kg ball just before impact.
(b) Assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision.
(1.75 kg ball)
(4.45 kg ball)
(c) How high does each ball swing after the collision, ignoring air resistance?
(1.75 kg ball)
(4.45 kg ball)
(a) Using the principle of conservation of mechanical energy, find the speed of the 1.75 kg ball just before impact.
(b) Assuming that the collision is elastic, find the velocities (magnitude and direction) of both balls just after the collision.
(1.75 kg ball)
(4.45 kg ball)
(c) How high does each ball swing after the collision, ignoring air resistance?
(1.75 kg ball)
(4.45 kg ball)
Answers
Answered by
bobpursley
I am wondering what you are having difficultly with. I will be happy to critique your thinking.
Answered by
joseph
im just not sure what formula exactly to use to solve each part a,b, and c
Answered by
Anonymous
babi
Answered by
Anonymous
A 0.75-{\rm kg} ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.7m on a frictionless horizontal surface
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