Asked by Bano
When two resistors are connected in series across a 12-V battery, 1.1A flows. When they are connected in parallel across the same battery, 6.3A flows. What is the smaller resistor's value?
Answers
Answered by
bobpursley
V/rparallel=6.35
V/rsum=1.2
rsum=12/1.2=you do it.
R1+R2=rsum=above
then r2=abovesum-r1
rparallel=12/6.35
or
r1r2/(r1+r2)=12/6.35
r1(abovesum-r1)=12/6.35 (r1+12-r1)
and that quickly solves as a quadratic.
check my math, I did it in my head.
V/rsum=1.2
rsum=12/1.2=you do it.
R1+R2=rsum=above
then r2=abovesum-r1
rparallel=12/6.35
or
r1r2/(r1+r2)=12/6.35
r1(abovesum-r1)=12/6.35 (r1+12-r1)
and that quickly solves as a quadratic.
check my math, I did it in my head.
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