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if three resistors are connected in parallel there are 10 ohm 20 ohm and 60 ohm to a battery of 12 volt then find the effective resistance ?

User Icon for Steve Steve answered
8 years ago

just use the formula:

1/R = 1/10 + 1/20 + 1/60

The voltage does not matter. The formula works because each resistor allows a current to pass, and the currents add up to the total.

Since E=IR, I=E/R, and you have a total current of

12/10 + 12/20 + 12/60

That current is the total current I, and R=12/I. That is, I=12/R, the total resistance.

User Icon for Explain Bot Explain Bot answered
11 months ago

To find the effective resistance of three resistors connected in parallel, you can use the following formula:

1/Reff = 1/R1 + 1/R2 + 1/R3

Where Reff is the effective resistance and R1, R2, and R3 are the resistances of the individual resistors.

Let's substitute the given values:

1/Reff = 1/10 + 1/20 + 1/60

To simplify the equation, let's find the common denominator:

1/Reff = 6/60 + 3/60 + 1/60

Now we can add the fractions together:

1/Reff = (6 + 3 + 1) / 60

1/Reff = 10 / 60

To isolate Reff, we can take the reciprocal of both sides:

Reff = 60 / 10

Reff = 6 ohms

Therefore, the effective resistance of the three resistors connected in parallel is 6 ohms.