Asked by Josh
Use implicit diff. to find dy/dx of each of the following. In the following x,y and (a) are all variables. Show step by step please! Thank you!
1) y^2 = x^2+a^2
2) y^2+ay = x^2+ax+a^2
1) y^2 = x^2+a^2
2) y^2+ay = x^2+ax+a^2
Answers
Answered by
Damon
2 y dy/dx = 2 x + 2 a da/dx
y dy/dx = (x+a da/dx)
dy/dx = (x + a da/dx)/y
or
dy/dx = (x + a da/dx)/(x^2+a^2)^.5
---------------------------------
2 y dy/dx + a dy/dx + y da/dx = 2 x^2 + a + x da/dx + 2 a da/dx
(2y+a)dy/dx = 2 x^2 +a +(x-y+2a)da/dx
dy/dx = [2 x^2 +a +(x-y+2a)da/dx]/(2y+a)
y dy/dx = (x+a da/dx)
dy/dx = (x + a da/dx)/y
or
dy/dx = (x + a da/dx)/(x^2+a^2)^.5
---------------------------------
2 y dy/dx + a dy/dx + y da/dx = 2 x^2 + a + x da/dx + 2 a da/dx
(2y+a)dy/dx = 2 x^2 +a +(x-y+2a)da/dx
dy/dx = [2 x^2 +a +(x-y+2a)da/dx]/(2y+a)
Answered by
bobpursley
I suspect in each, a is a constant, so da/dx=0
Answered by
Damon
I figured the same but he said specifically that a was variable.
Answered by
Josh
My answers were like these
1)
2yy'=2x+2a
y'=2x+2a/2y
2)
2yy'+ay'+y=2x+a+x+2a-y
2yy'+ay'=3x+3a-y
y'(2y+a)=3x+3a-y
y'=3x+3a-y/2y+a
And my teacher said I made mistakes with my answers but I couldn't figure out.
1)
2yy'=2x+2a
y'=2x+2a/2y
2)
2yy'+ay'+y=2x+a+x+2a-y
2yy'+ay'=3x+3a-y
y'(2y+a)=3x+3a-y
y'=3x+3a-y/2y+a
And my teacher said I made mistakes with my answers but I couldn't figure out.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.