Question
2 NaOH + CuSO4 Na2SO4 + Cu(OH)2
100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?
100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?
Answers
How many mols Cu(OH)2 do you need? That's mols = g/molar mass = 100/97.56 = approx 1 mol but you need to do it more accurately.
Convert mols Cu(OH)2 to mols NaOH = twice that = about 2 mol (again, do it more accurately).
M NaOH = mols/L. You know mols NaOH and M NaOH, solve for L NaOH and convert to mL.
Do the same to convert mols Cu(OH)2 to mols CuSO4 then M = mols/L. Finally, convert L CuSO4 to mL.
Convert mols Cu(OH)2 to mols NaOH = twice that = about 2 mol (again, do it more accurately).
M NaOH = mols/L. You know mols NaOH and M NaOH, solve for L NaOH and convert to mL.
Do the same to convert mols Cu(OH)2 to mols CuSO4 then M = mols/L. Finally, convert L CuSO4 to mL.
Related Questions
Alright, I've made a list of reactions that would produce precipatations.
NaCl + Zn
CaCl2 + NaOH...
If 100g of CuSO4 took part in the following reaction how much Cu(0H)2 would be formed
CuSO4 + 2NaOH...
2NaOH + CuSO4 = Na2SO4 + Cu(OH)2
100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M N...
Look at the chemical reaction above. For each substance in the reaction, decide if bonds are breakin...