Asked by Kelsey
I need help with this problem:
Two planes start from Los Angeles International Airport and fly in opposite directions. The second plane starts ½ hour after the first plane, but its speed is 80 kilometers per hour faster. Find the airspeed of each plane if 2 hours after the first plane departs the planes are 3200 kilometers apart.
Two planes start from Los Angeles International Airport and fly in opposite directions. The second plane starts ½ hour after the first plane, but its speed is 80 kilometers per hour faster. Find the airspeed of each plane if 2 hours after the first plane departs the planes are 3200 kilometers apart.
Answers
Answered by
bobpursley
distance slow plane=vt
distance fast plane=.5*(v+80)t +(v+80)t
3200=sum of the two distances, or
3200=v*2+.t(v+80)*2 + (v+80)*2
solve for v, then for the faster plane, its speed is v+80
distance fast plane=.5*(v+80)t +(v+80)t
3200=sum of the two distances, or
3200=v*2+.t(v+80)*2 + (v+80)*2
solve for v, then for the faster plane, its speed is v+80
Answered by
Marney
Whats 1/5 (one fifth) of 200?
Answered by
bobpursley
40 times five is 200
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.