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Original Question
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 1800 km away. The...Question
Two planes left simultaneously from the same airport and headed in the same direction towards another airport 3600 km away. The speed of one of the planes was 200 km/hour slower than the speed of the other plane, and so it arrived at its destination 1.5 hours after the faster plane. Find the speeds of both planes.
Answers
oobleck
since time = distance/speed, if the slower plane has speed s, we have
3600/s = 3600/(s+200) + 1.5
3600/s = 3600/(s+200) + 1.5
R_scott
f is faster speed , s is slower speed
f = s + 200
3600 / s = (3600 / f) + 1.5 ... 3600 f = 3600 s + 1.5 f s
substituting ... 3600 s + 720000 = 3600 s + 1.5 s^2 + 300 s
s^2 + 200 s - 480000 = 0
solve for s , substitute back to find f
f = s + 200
3600 / s = (3600 / f) + 1.5 ... 3600 f = 3600 s + 1.5 f s
substituting ... 3600 s + 720000 = 3600 s + 1.5 s^2 + 300 s
s^2 + 200 s - 480000 = 0
solve for s , substitute back to find f
hi
600
hi
and 800
hi responder :D
yes he is right. Its going to be 600 and 800
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dozier
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