Asked by sly
Solve the following systems:
1) x+z=2
2x+y=3
X-y+z=1
1) x+z=2
2x+y=3
X-y+z=1
Answers
Answered by
Damon
z = (2-x)
y = (3-x)
x -(3-x) +(2-x) = 1
x - 3 + x + 2 - x = 1
x - 1 = 1
x = 2
z = 0
y = 1
y = (3-x)
x -(3-x) +(2-x) = 1
x - 3 + x + 2 - x = 1
x - 1 = 1
x = 2
z = 0
y = 1
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