Asked by diana

Solve the following systems of equations.

3x + 4y = 4
2x + y = 6

Answers

Answered by Bosnian
2 x + y = 6 Subtract 2 x to both sides

2 x + y - 2 x = 6 - 2x

y = 6 - 2x


3 x + 4 y = 4

3 x + 4 ( 6 - 2 x ) = 4

3 x + 24 - 8 x = 4

- 5 x + 24 = 4 Subtract 24 to both sides

- 5 x + 24 - 24 = 4 - 24

- 5 x = - 20 Divide both sides by - 5

- 5 x / - 5 = - 20 / - 5

x = 4


y = 6 - 2x

y = 6 - 2 * 4

y = 6 - 8 = - 2


Solution :

x = 4 , y = - 2




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