In neutralization reactions,

Question

acid + base �¨ salt + water
HCl can be neutralized with NaOH. How many moles of NaOH will it take to neutralize 0.68 L of 0.29 M HCl?
Is there a formula that I need to use here?

Answer 1

HCl + NaOH --- > H2O + NaCl balanced as is

One mole of NaOH for every one mole of HCl because the equation balances with one of each

.68 * .29 = .1972 moles of HCl so we need .1972 moles of NaOH