Asked by Anonymous
How would you prepare 100 mL of a 0.01N sulfuric acid solution?
Answers
Answered by
DrBob222
Technically you can't do this without knowing the reaction; however, you probably meant to use both H as in
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
So how many equivalents do you want? That's N x L = 0.01N x 0.1L = 0.001 equivalents.
Then g = eq x eq wt = 0.001 x 49 = ?
You can work this in 1 step if you put both of these formulas together to obtain mL x N x meqwt=- grams
100 x 0.01 x 0.049 = ?
2NaOH + H2SO4 ==> Na2SO4 + 2H2O
So how many equivalents do you want? That's N x L = 0.01N x 0.1L = 0.001 equivalents.
Then g = eq x eq wt = 0.001 x 49 = ?
You can work this in 1 step if you put both of these formulas together to obtain mL x N x meqwt=- grams
100 x 0.01 x 0.049 = ?
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