You want 800 x 0.69 = approx (you need to do it) 552 mmols total. I may have different K values than you. I will use 7.20 for pK2.
7.6 = 7.2 + log (base)/(acid)
Solve for b/a and I get approx
b/a = 2.5 (in millimols--not concn)
a + b = 552 (in millimols).
Solve these two equations simultaneously to determine millimils a and mmols b. I think you can go from there. Post your work if you get stuck and explain your trouble.
You are instructed to create 800. mL of a 0.69 M phosphate buffer with a pH of 7.6. You have phosphoric acid and the sodium salts NaH2PO4, Na2HPO4, and Na3PO4 available. what is the molarity needed for the acid component of the buffer?What is the molarity needed for the base component of the buffer? How many moles of acid are needed for the buffer?How many moles of base are needed for the buffer? How many grams of acid are needed for the buffer? How many grams of base are needed for the buffer?
1 answer
1 answer