Asked by Alexis
A 15N force acting at 15 degrees north of east and a 18N force acting at 79 degrees north of west act concurrently on an object. What is the magnitude and direction of a third force that produces equilibrium on the object? Show sketch and work.
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x-component:: 15*cos(15 deg)+18cos(101 deg) = 11.05
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y-component:: 15*sin(15 deg)+18sin(101 deg) = 21.55
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magnitude = sqrt[11.05^2+21.55^2] = 24.22
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direction = arctan(21.55/11.05) = 62.85 degrees north of east
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x-component:: 15*cos(15 deg)+18cos(101 deg) = 11.05
---
y-component:: 15*sin(15 deg)+18sin(101 deg) = 21.55
--------
magnitude = sqrt[11.05^2+21.55^2] = 24.22
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direction = arctan(21.55/11.05) = 62.85 degrees north of east
Answers
Answered by
Damon
That is the resultant, but you need the opposite to that so move it around 180 to cancel it
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