Question

The reduction potentials for the species involved in an electrochemical cell are as follows:

M+ + e– --> M is 0.30 V
J+ + e– --> J is 0.40 V.

All solutions are 1.00 M and J+ / J is connected to M+ / M.

What is Ecell (in V)?

Which species is easier to oxidize?

The electrons flow from ? (M or J) to ? (M or J).

Answer 1

Take the most negative reduction potential and turn it around. Leave the other as is.
J + e ==> J E = 0.40 v
M ==> M^+ + e E = -0.30 v
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now add the equation and you will obtain a positive voltage for Ecell.
The cell notation is as follows:
M/M^+(1 M)||J^+(1 M)/J
So M is the anode (-) and J is the cathode (+). Electrons flow from - to +.

Write them both as oxidations. The easier one to oxidize will have the larger E value.

Answer 2

its unlimited tries, so if you are just looking for the answers, for the first part, just take the larger minus the smaller value, the species that is easier to oxidize should be the smaller value V, and the flow goes from less V to more V if that made any sense

Answer 3

ANSWER:

+.1

M

M

J

Answer 4

Jenn is correct!

ANSWER:

+.1

M

M

J