What is the molarity of 50.0 mL solution of aluminum sulfite that contains 80.0 g of this salt? (Al=27.0, S=32.0,O=16.0)

Answer 1

Al2(SO3)3

2 Al = 54
3 S = 96
9 O = 144
-----------add
294 grams/mol
so
80 grams is 80/294 = 0.272 mol of aluminum sulfite in 50 mL
a liter is 1000 mL
0.272 *1000/50 = 5.44 mols/liter

Answer 2

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