Asked by Aly
Solve for x:
log base27 (2x-1) = 4/3
log base27 (2x-1) = 4/3
Answers
Answered by
Damon
b^logb(x) = x
so
27^log(2x-1) = 27^(4/3) = 3^4 = 9*9 = 81
so
2x-1 = 81
2 x = 82
x = 41
so
27^log(2x-1) = 27^(4/3) = 3^4 = 9*9 = 81
so
2x-1 = 81
2 x = 82
x = 41
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