Asked by Anonymous
A baseball is hit vertically upward and is caught by the catcher 2.68s later. Assume the ball was hit and caught at a height of 1.00m.
what is the velocity of the ball when it is hit off the bat?
what is the balls maximum displacement?
what is the velocity of the ball when it is hit off the bat?
what is the balls maximum displacement?
Answers
Answered by
Henry
Tr = 2.68/2 = 1.34 s. = Rise time.
V = Vo + g*Tr = 0 @ max. ht.
Vo = -(g*Tr) = -(-9.8*1.34) = 13.13 m/s.
D = h - ho = 1m - 1m = 0
V = Vo + g*Tr = 0 @ max. ht.
Vo = -(g*Tr) = -(-9.8*1.34) = 13.13 m/s.
D = h - ho = 1m - 1m = 0
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