A 8.05- g bullet from a 9-mm pistol has a velocity of 346.0 m/s. It strikes the 0.785- kg block of a ballistic pendulum and passes completely through the block. If the block rises through a distance h = 16.04 cm, what was the velocity of the bullet as it emerged from the block?

Answer 1

initial momentum = .00805 * 346

final momentum just after collision
= M V + m v

so
.00805 = MV + m v

we can do MV from how far up it goes
(1/2) M V^2 = M g h =M (9.81)(.1504)
cancel M and find V

now we have it
initial momentum = final momentum
.00805 * 346 = .785 V + .00805 v
we know V
solve for v