Y^2 = Yo^2 + 2g*h = 0
Yo^2 - 64*11.7 = 0
Yo^2 = 748.8
Yo = 27.4 Ft/s = Ver. component of
the initial velocity.
Vo = Yo/sinA = 27.4/sin51 = 35.2 Ft/s =
Initial velocity = Speed at which the
animal must leave gnd.
The best leaper in the animal kingdom is the puma, which can jump to a height of 11.7 ft when leaving the ground at an angle of 51°. With what speed, in SI units, must the animal leave the ground to reach that height?
2 answers
Vo = 35.2 Ft/s * 1m/3.3Ft = 10.7 m/s.
2 answers