Asked by Brady
                Please help me with the following(there is 9 problems so be prepared):
1.2^(1/3)∙4^(1/3)
I think it is 4 for the answer.
2. 11^(1/2)∙11^(1/2)
I think it is 11 for the answer.
3. 2^(1/2)∙2^(1/2)
I think it is 2 for the answer.
4. 3^(1/3)∙9^(1/3)
I think the answer is either 3 or 9.
5. 18^(1/2)∙18^(1/2)
I think the answer is 18.
6. 9^(-2.5)
I think the answer is 1/243.
7. 8^(4/3)
I think the answer is 16.
8. 20^(1/2)∙20^(1/2)
I think the answer is 20.
9. 27^(2/3)
I think the answer is 9.
I would appreciate it if any of you could help me. Thank you if you guys can help.
            
        1.2^(1/3)∙4^(1/3)
I think it is 4 for the answer.
2. 11^(1/2)∙11^(1/2)
I think it is 11 for the answer.
3. 2^(1/2)∙2^(1/2)
I think it is 2 for the answer.
4. 3^(1/3)∙9^(1/3)
I think the answer is either 3 or 9.
5. 18^(1/2)∙18^(1/2)
I think the answer is 18.
6. 9^(-2.5)
I think the answer is 1/243.
7. 8^(4/3)
I think the answer is 16.
8. 20^(1/2)∙20^(1/2)
I think the answer is 20.
9. 27^(2/3)
I think the answer is 9.
I would appreciate it if any of you could help me. Thank you if you guys can help.
Answers
                    Answered by
            Reiny
            
    #1.
2^(1/3)*4^(1/3)
= 8^(1/3) = 2
#2,3 , ok
#4 same reasoning as #1
3((1/3) * 9^(1/3)
= 27(1/3) = 3
#5, 6, 7, 8, 9 are all ok
    
2^(1/3)*4^(1/3)
= 8^(1/3) = 2
#2,3 , ok
#4 same reasoning as #1
3((1/3) * 9^(1/3)
= 27(1/3) = 3
#5, 6, 7, 8, 9 are all ok
                    Answered by
            Brady
            
    Thank you Reiny. I know it was a lot, so thank you for going through them and checking my answers. I will make sure to see what I did wrong on 1 and 4. Also, thank you for giving me another way of doing these type of problems. Thank you!
    
                    Answered by
            Reiny
            
    remember , the method I used only works if the exponents are the same,
that is,
a^m * b^m = (ab)^m
    
that is,
a^m * b^m = (ab)^m
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