Asked by Brenard
A jet climbs at an angle of 26 degrees to the ground. The cruising height for the jet is 8000m, the climbing speed is 300km/hr and the cruising speed is 450km/hr. How far is it from the airport 5 minutes after taking off? Please explain thoroughly.
Answers
Answered by
Steve
it takes 8/300 hours to get to cruising height. That's 1.6 minutes
in the remaining 3.4 minutes it travels 3.4/60*450 = 25.5 km
during the climb, it traveled 8cot26° = 16.4 km along the ground.
After flying the additional 25.5 km, it is 41.9 km away along the ground.
So, the actual straight-line distance d is given by
d^2 = 41.9^2 + 8^2
in the remaining 3.4 minutes it travels 3.4/60*450 = 25.5 km
during the climb, it traveled 8cot26° = 16.4 km along the ground.
After flying the additional 25.5 km, it is 41.9 km away along the ground.
So, the actual straight-line distance d is given by
d^2 = 41.9^2 + 8^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.