Asked by Anonymous
A 30 kg person climbs up a 5 m rope at a constant speed. If the student’s power output is 2 kW, how long does it take for the student to climb the rope? How much work does the student do?
Answers
Answered by
drwls
The work done is obviously W = M g H, the potential energy increase.
For the time T, solve
W/T = Power = 2000 W
For the time T, solve
W/T = Power = 2000 W
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